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Cannot Read Output Vhdl

How do pilots identify the taxi path to the runway? The value of C is read from this dummy signal named C_dummy. check your modelsim.ini file for vhdl93: [vcom] ; Turn on VHDL-1993 as the default. In this case, the call of reset_status on status tells tells the syntheser that it is an input. > > Well, after adding this to the sensitivity list I've got the this contact form

As Mike wrote, status_i is on the right side and therefore read. About Us The Coding Forums is a place to seek help and ask questions relating to coding and programming languages. Stay logged in Welcome to The Coding Forums! The VHDL code that was generated defined my output port as type OUT.

You didn't do this, so don't worry about it. But this is an output. Not the answer you're looking for? share|improve this answer answered Nov 7 '10 at 20:26 Martin Thompson 13k11737 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google

The output of the inverter also feeds the input of other gates. >> The VHDL code that was generated defined my output port as type OUT. >> However, when compiling for What crime would be illegal to uncover in medieval Europe? Coding Forums Forums > Archive > Archive > VHDL > Forums Forums Quick Links Search Forums Recent Posts Members Members Quick Links Notable Members Current Visitors Recent Activity New Profile Posts Again: think hardware.

Please upgrade to a Xilinx.com supported browser:Chrome, Firefox, Internet Explorer 11, Safari. Certainly for any modulenot directly connected to the device pins you should be able to use the value of module outputs. You may want to search for "status" in all code, to see if a "status" port with mode out is referenced for read. I think VHDL is a bit over-restrictive in this sense.

car_passed => entry_car_entered(i) -- This line causes the problem. ); end generate CREATE_ENTRANCES; -- ..... When I simulate this, C won't go highwhen A and B are high.Here is the codelibrary IEEE;use IEEE.STD_LOGIC_1164.ALL;use IEEE.STD_LOGIC_ARITH.ALL;use IEEE.STD_LOGIC_UNSIGNED.ALL;---- Uncomment the following library declaration if instantiating---- any Xilinx primitives in In other words, ideally I would like to assign two debug the in and out values of the FIFO, ie. You really must understand why this is a problem. -aps: so what's the signal A supposed to do in your entity?

Xilinx.com uses the latest web technologies to bring you the best online experience possible. my company All rights reserved Privacy Policy · Terms of Service · User Agreement What movie is this? Change object mode to buffer.

DBG_FIFO_IN <= DIN; DBG_FIFO_OUT <= DOUT; For obvious reasons, the second assignment gives me the following error message: [exec] ERROR:HDLParsers:1401 - Object DOUT of mode OUT can not be read. weblink So let me show how to reduce the amount of buffer usage with an example. Yes, my password is: Forgot your password? Thanks Olaf Olaf Petzold, Dec 19, 2005 #9 Mike Treseler Guest Olaf Petzold wrote: > Well, I have to ignore the warning or replace the procedure with > procedure body's

Please join our friendly community by clicking the button below - it only takes a few seconds and is totally free. To start viewing messages, select the forum that you want to visit from the selection below. I make no claims that this would necessarily behave as desired. navigate here Hi, I have a schematic where an inverter is connected to an output port.

Carson, Aug 10, 2005, in forum: VHDL Replies: 9 Views: 4,685 Divyang M Aug 21, 2005 ModelSim Error : "Fatal error in Process determine_phase_shift" during post synthesis of Xilinx vhd fpgaengineer, Showing results for  Search instead for  Do you mean  Register · Sign In · Help Community Forums : Xilinx Products : Design Tools : Synthesis : simple and gate can't be Success!

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Outputs cannot be read. it's probably best not to refer to this - the thread contains a number of errors. car_passed: out std_logic --Output to higher level ); end component; begin CREATE_ENTRANCES: for i in 0 to entryCount-1 generate entryi: entry port map ( clk => clk, -- .... Examples in books etc show that out is fine.

Can clients learn their time zone on a network configured using RA? The use of an internal signal I will try. Ralf Ralf Hildebrandt, Dec 18, 2005 #3 Duane Clark Guest Olaf Petzold wrote: > Hi, > > the code below produces the warning: > > Synthesis Warning: Reset signal 'status' his comment is here this isn't particularly > good style, but is the simplest solution.

VaVe. (VHDL ain't Verilog.) Output ports can only be written, not read. Does the same apply to >> VHDL? lordslimey posted Oct 3, 2016 How to remove an empty line which is created when i deleted a element from my xml file? Doing assembly and really doing assembly 2.

In my code the recod is more complex. That's largest value in this case because of using "downto", so the init will be to "1111" = 15. This feature is not supported. Which one ? > > Well, after adding this to the sensitivity list I've got the error: > Cannot read output "status".

However, when compiling for simulation, I get an error at the other gates saying "Cannot read output". asked 2 years ago viewed 1976 times active 2 years ago Upcoming Events 2016 Community Moderator Election ends Nov 22 Visit Chat Linked 1 VHDL Counter circuit error Related 3How can Modelsim should have told you this also together with the 1st warning. -> Make a copy from the output signal, read the copy. You wrote, output signals can not be read.

process(Clk) begin if ( rising_edge(Clk) ) then C_dummy <= A + B + C_dummy; --Use the intermediate signal in actual Also, are you suggesting that you are connecting outputs together? #2 Like Reply jjtjp likes this. entry_car_entered : out std_logic_vector(0 to entryCount-1) ); end entity controller_entity; architecture controller_v1 of controller_entity is signal cars_entered : std_logic_vector(0 to entryCount-1); component entry is port( clk : in std_logic; -- .... If you use the buffer type, be sure to set the compiler to use, as a minimum, the 2002 version of VHDL as buffers were not well supported before then.

EDIT: So my workaround works, which was to just create a bunch more intermediate signal lines which I used in my combinational logic. Are there continuous functions for which the epsilon-delta property doesn't hold? Instead use a local signal that can be read both by the debug and regular port. –trondd Mar 11 '11 at 9:32 add a comment| up vote 2 down vote You